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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑
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足球看完了来看看题目。8 e& x! ]( c& ]
2 \4 f5 s1 p* E& cThe length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)# m- `, P7 k" H( P6 \
The drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)
7 P& r6 i0 L1 ~6 x) FWe can see it is not easy to install the 22 meters heat trace according as figure 1
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. h+ J; J# C) R3 {) F( n( i" x) }: ?As a normal question we just discuss:* h! p* l1 l# D. ?, M8 y
How do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ? 8 w: F3 I8 F5 W# a
I call this is JACK LAI Spiral Method 螺旋法
( J2 {, Z: y5 LThe outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.
% \+ y% x0 N$ ~! Q: r. rThere are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch.
: C0 u0 Q. B$ g2 P" r! ?Because the pipe is horizontal, position 0 can not be placed. See figure 24 U, n8 _) f* T; {3 Y0 C/ R( e7 o5 n
Because the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3
}4 L+ ~1 g/ Y2 f( J6 k n1 c/ cThe total heat trace that can be installed here is about 1 y( q9 o+ g6 B% {5 t; S2 a) R, E
1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters: P+ n4 j* b8 M% p! B" x2 L
So, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem. 3 c- K5 l7 P. c6 m+ L
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Note :* S- M8 I6 C( f- s1 l! z
1. The minimum bend radius:& c- h$ y6 p1 X8 p: B$ V
Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is$ {) f. i# f" ]! ]
5/16 *6 = 30/16 almost = 2 inches
C( U+ k; C2 L1 \& FSo the maximum bend radius is 2 inches.
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8 r' @# \2 t3 q! p) q# jSummary
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For 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe( k* I2 k9 D1 L) J7 T/ o4 T* A4 e
if the pipe is horizontal, The length of heat trace can be installed is about( f6 S2 x4 t8 M' J8 l$ ~+ v0 ], M; t
1 * 9 = 9 meters
/ B% B7 ?! ^: Q! m+ v* J) C yIf the pipe is vertical, The length of heat trace can be installed is about4 W) J7 c* `" N6 V
1 * 10 = 10 meters. ! I, k) i) ]+ _
For 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe0 d4 t8 G2 B {2 Z8 ]
if the pipe is horizontal , The length of heat trace can be installed is about
, {) m; n3 j- j& W7 P. h1 * 4 = 4 meters9 [( F1 V0 q9 f- J, D- ^" v/ S5 C
If the pipe is vertical, The length of heat trace can be installed is about) Y M( P+ g* H4 m. w3 j
1 * 5 = 5 meters. |
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